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If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, what is the height of the image?
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If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the image is formed 4 millimeters in front of the lens, what is the height of the image?

User Surita
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7.6k points

1 Answer

3 votes

The answer is

18 / x = 12 / 4

12x = 72

x = 6mm

User DeepSpace
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