Answer:
(a) 1870 cubes; (b) 233¾ in³
Explanation:
Data:
l = 11 in
w = 8½ in
h = 2½ in
(a) Volume of box in cubes
Convert each dimension of the box to cubes
l = 11 ÷ ½ = 11 × 2 = 22 cubes
w = 8½ ÷ ½ = 8½ × 2 = 16 + 1 = 17 cubes
h = 2½ ÷ ½ = 2½ × 2 = 4 + 1 = 5 cubes
Calculate the volume of the box
V = lwh = 22 × 17 × 5 = 1870 cubes
The box can contain 1870 cubes.
(b) Volume of box in cubic inches
Calculations:
V = 11 × 8½ × 2½
Convert each number to an improper fraction:
![(11 )/(1 )* (17 )/(2 ) * (5 )/(2 )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/92tu84npo65kla8w6t4q6ze3znhrckdey4.png)
Multiply the numerators and multiply the denominators
![(11 * 17 * 5 )/(4 ) = (935 )/(4 )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gfk8mqq7xkc6rbixaoyr7y2cctaucxtvtf.png)
Convert the answer back to a mixed number
(233 with a remainder of 3)
The volume of the box is 233¾ in³.