What is the quadratic equation when the given equation is: y = 6(x - 1) {}^(2) - 4

asked Dec 26, 2020 195k views

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What is the quadratic equation when the given equation is:

$y = 6(x - 1) {}^(2) - 4$

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$\bf y=6(x-1)^2-4\implies y=6(x-1)(x-1)-4 \\\\\\ y=6\stackrel{\mathbb{F~O~I~L}}{(x^2-2x+1)}-4\implies y=6x^2-12x+6-4\implies y=6x^2-12x+2$

Synic answered Dec 30, 2020

by Synic

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