Question

circuit in Mike’s home is almost at maximum current. If it is a 120 V circuit with about 1/3 of an amp available to safely use, which bulb would be the maximum wattage Mike could use?

Answer 1

40 W

Step-by-step explanation:

Answer 2

40 W

Step-by-step explanation:

The maximum wattage (power) that Mike can use is given by:

`P=VI`

where

V is the voltage

I is the maximum current

In this problem, we have:

`V=120 V` is the voltage

`I=(1)/(3)A=0.33 A` is the maximum current available

Therefore, the maximum power that could be used is

`P=VI=(120 V)(0.33 A)=40 W`