Question

What is the quotient?

Answer 1

Choice B is the answer.

Explanation:

We have given an expression.

`(2y^(2)-6y-20 )/(4y+12)` ÷
`(y^(2)+5y+6 )/(3y^(2)+18y+27 )`

We have to find the quotient of the given expression.

`(2y^(2)-10y+4y-20 )/(4(y+3))` ÷
`(y^(2)+2y+3y+6 )/(3(y^(2)+6y+9) )`

`(2y(y-5)+4(y-5))/(4(y+3))` ÷
`(y(y+2)+3(y+2))/(3(y^(2)+3y+3y+9) )`

`((2y+4)(y-5))/(4(y+3))` ÷
`((y+2)(y+3))/(3(y+3)(y+3))`

By changing distribution into multiplication, we have

`(2(y+2)(y-5))/(4(y+3))` ×
`(3(y+3)(y+3))/((y+2)(y+3))`

`(3(y-5))/(2)` which is the answer.