Answer:
x ∈ (-∞, -2) ∪ (2, ∞)
Explanation:
To solve this problem we must factor the expression that is shown in the denominator of the inequality.
So, we have:
![x ^ 2-4 = 0\\x ^ 2 = 4](https://img.qammunity.org/2020/formulas/mathematics/high-school/j2ce8w24dh5idawf8tooscaqkntzysjxw7.png)
So the roots are:
![x = 2\\x = -2](https://img.qammunity.org/2020/formulas/mathematics/high-school/yhudw7lbg7o2vrq6fcqfgys0snl9z9tftk.png)
Therefore we can write the expression in the following way:
![x ^ 2-4 = (x-2)(x + 2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qu78vsnqhrnttwl0yfblez9fsoqyp204qr.png)
Now the expression is as follows:
![((x + 5) ^ 2)/((x-2)(x + 2))\geq0](https://img.qammunity.org/2020/formulas/mathematics/high-school/4gra0e1y98kcbfin7hju7xn5n12qn7fpkt.png)
Now we use the study of signs to solve this inequality.
We have 3 roots for the polynomials that compose the expression:
.
Observe the attached image.
We know that the first two roots are not allowed because they make zero the denominator, we also know that (x + 5) ^ 2 is always positive because it is squared, so it is not necessary to include the numerator in the study of signs.
Note that:
when
![x\geq2](https://img.qammunity.org/2020/formulas/mathematics/high-school/s5piw4804p9syxghjdrkg5ftp1mwnaf8t9.png)
when
![x\geq-2](https://img.qammunity.org/2020/formulas/mathematics/high-school/bv4ov3ycxqa6nx0gx56108fgangy3gae0k.png)
Finally after the study of signs we can reach the conclusion that:
x ∈ (-∞, -2) ∪ (2, ∞)