71.6k views
2 votes
Write the equation in vertex form.
f(x) = x^2 + 10x - 5

1 Answer

1 vote

Answer:

y = (x +5)² - 30 where vertex for the parabola is (-5,-30).

Explanation:

We have given a function:

f(x) = x² + 10x - 5

We have to find the vertex form given form.

Let y = f(x)

y= x² + 10x - 5

The general vertex form :

y = a(x-h)²+h

First, we have to complete the square we have,

y= x² + 10x - 5

y = x² +2(x)(5)-5 +(5)²-(5)²

y = (x +5)²-5-25

y = (x +5)² - 30

y = (x +5)² - 30 where vertex for the parabola is (-5,-30).

User Clcto
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories