Answer:
x ∈ (-∞, -1) ∪ (1, ∞)
Explanation:
To solve this problem we must factor the expression that is shown in the denominator of the inequality.
So, we have:

So the roots are:

Therefore we can write the expression in the following way:

Now the expression is as follows:

Now we use the study of signs to solve this inequality.
We have 3 roots for the polynomials that make up the expression:

We know that the first two are not allowed because they make the denominator zero.
Observe the attached image.
Note that:
when

when

and
is always

Finally after the study of signs we can reach the conclusion that:
x ∈ (-∞, -1) ∪ (1, 2] ∪ [2, ∞)
This is the same as
x ∈ (-∞, -1) ∪ (1, ∞)