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I really need help with this please.

I really need help with this please.-example-1
User Najera
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1 Answer

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9 votes

Answer:

y = - 6x + 7.5

Explanation:

the perpendicular bisector of BC passes through the midpoint of BC at right angles to BC.

calculate the slope m of BC using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = B (- 2, 1 ) and (x₂, y₂ ) = C (4, 2 )


m_(BC) =
(2-1)/(4-(-2)) =
(1)/(4+2) =
(1)/(6)

given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/((1)/(6) ) = - 6

the midpoint of BC is the average of the x and y coordinates

midpoint = (
(-2+4)/(2) ,
(1+2)/(2) ) = (
(2)/(2) ,
(3)/(2) ) = ( 1, 1.5 )

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 6 , then

y = - 6x + c ← is the partial equation

to find c substitute (1, 1.5 ) into the partial equation

1.5 = - 6 + c ⇒ c = 1.5 + 6 = 7.5

y = - 6x + 7.5 ← equation of perpendicular bisector of BC

User Jules Patry
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