Answer:
2(x - 2)(2x + 1)
Explanation:
Given
4x² - 6x - 4 ← factor out 2 from each term
= 2(2x² - 3x - 2)
To factor the quadratic inside the parenthesis
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 2 = - 4 and sum = - 3
The factors are - 4 and + 1
Use these factors to split the x term
2x² - 4x + x - 2 ( factor the first/second and third/fourth terms )
= 2x(x - 2) + 1(x - 2) ← factor out (x - 2)
= (x - 2)(2x + 1)
Hence
4x² - 6x - 4 = 2(x - 2)(2x + 1) ← in factored form