Question

Log3+logx-log(x+1)=log2

Answer 1

• x = 2

Explanation:

These are the properties of logarithms that you have to use to solve the equation:

`logA+logB=log (AB)\\ \\ logA-logB=log((A)/(B) )`

`logA=logB`⇒
`A=B`

With that you can follow these steps and find the value of x:

`log3+logx-log(x+1)=log2\\ \\\\ log(3x)/(x+1) =log2\\ \\ \\ (3x)/(x+1) =2\\ \\ \\ 3x=2(x+1)\\ \\ \\ 3x=2x+2\\ \\ \\ x=2`