Question

What are the first three terms of the sequence...plz help pt.1​

Answer 1

`a_(n) \: = \: 2(a_(n - 1))^(2) \\ a_(1) = 4 \: (given) \\ a_(2) = \: 2(a_(2 - 1))^(2) \\ = 2(a_( 1))^(2) \\ = 2 * {4}^(2) \\ = 32 \\ \\ a_(3) = \: 2(a_(3 - 1))^(2) \\ = 2(a_( 2))^(2) \\ = 2 * {32}^(2) \\ = 2 * 1024 \\ = 2048`

so first 3 terms are

4, 32, 2048

Answer 2

The correct answer is option 3

4, 32, 2048

Explanation:

It is given that,

a₁ = 4

aₙ = 2(aₙ₋₁)²

To find the second term

we have, aₙ = 2(aₙ₋₁)²

a₁ = 4

a₂ = 2(a₁)² = 2(4)² = 2 * 16 = 32

To find the third term

aₙ = 2(aₙ₋₁)²

a₂ = 32

a₃ = 2(a₂)² = 2(32)² = 2 * 1024 = 2048

Therefore the first three terms of the sequence are,

4, 32, 2048

The correct answer is option 3