Use the discriminant to determine the number of real-number solutions for equation:8×2+8×+2=0 8x2 + 8x + 2 = 0 ​

Question

Use the discriminant to determine the number of real-number solutions for equation:8×2+8×+2=0


`8x2 + 8x + 2 = 0`
​

Answer 1

One solution is correct.

Explanation:

Answer 2

Explanation:

For

ax²+bx+c=0, the values of x which are the solutions to the equation are given by: x=−b±√b2-4ac÷2a

The discriminate is the portion of the quadratic equation within the radical:

b²−4ac

If the discriminate is:

- Positive, you will get two real solutions

- Zero you get just ONE solution

- Negative you get complex solutions

To find the discriminant for this problem substitute:

8 for a

8 for b

2 for c

8²−(4·8⋅2)⇒64−64⇒0

Because the discriminate is

0

there will be just ONE solution.