Question

Y=|x−3|+|x+2|−|x−5|, if 3

Answer 1

Explanation:

I take it you want x = 3

y = abs(3 - 3) + abs(3 + 2) - abs(3 - 5)

y = 0 + 5 - abs(-2)

y = 0 + 5 - (2)

y = 0 + 5 - 2

y = 3

If you meant something else please leave a note.

Now all you do is redo the problem for 5

y = abs(5 - 3) + abs(5 + 2) - abs(5 - 5)

y = abs(2) + abs(7) - abs(0)

y = 2 + 7 - 0

y = 9

Now set up your inequality

3 < y < 9