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Please help me with this physics question ASAP​

Please help me with this physics question ASAP​-example-1
User Wood
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1 Answer

12 votes
12 votes

Answer:

See below

Step-by-step explanation:

With switches open, the circuit is a simple series circuit ....the ammeters will have the same readings

V = IR

I = V/R = 5 / (10+5+5) = .25 A

b) With S1 closed 5 ohm and 10 ohm in parallel become = 5 *10 / (5+10) = 3.33 ohm

then the series circuit current becomes

5 v / ( 10 + 3.33 + 5 ) = ammeter 1 = .273 amps

ammeter 2 will get a portion of this ...the smaller resistor will get 2/3 ...the 10 ohm resistor will get 1/3 .273 * 10 / 15 =.182 amps

User Srushti Shah
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