so
It can be simplified using the distributive property since "ac+ad" have a common factor of "a" and "bc+bd" have a common factor of "b" which makes it
and since "a(c+d) + b(c+d)" have a common factor of "(c+d)" we can use the distributive property which makes it
plug in "a+b" for 20 and "c+d" for 30 and we get