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‼️Stoichiometry / moles problem: ‼️
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‼️Stoichiometry / moles problem: ‼️

‼️Stoichiometry / moles problem: ‼️-example-1
User Alexandre DuBreuil
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1 Answer

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Amount of NH3 = 6.39 mol

Ratio of NH3 : Ratio of product
4 : 10

Hence, amount of product formed = 6.39/4 * 10 = 15.975mol = 16.0mol (3sf)
User Nikobelia
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