a woman traveling at 70m/s, applies the break on her car and stops in the time of 2seconds. what is her deceleration?

asked Feb 13, 2020 139k views

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2 votes

From the laws of motion:

v= u + at

Therefore:

0 = 70 + (2 * a)

a in this case = deceleration

$0 = 70 + 2a \\ \\ - 70 = 2a$

$a = - 35m {s}^( - 2)$

Renie answered Feb 19, 2020

by Renie

7.3k points

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