Given the following quadratic equation: y = (x+3)^(2) -4 What would be the vertex (h, k)? Vetex = (_,_)

Question

Given the following quadratic equation:


`y = (x+3)^(2) -4`
What would be the vertex (h, k)?
Vetex = (_,_)

Answer 1

The vertex of given equation is (-3,-4).

Explanation:

We have given an equation in vertex form.

y = (x+3)²-4

We have to find vertex of the given equation.

y = a(x-h)²+k is vertex form of the equation where (h,k) denotes vertex of the equation.

y = (x-(-3))²+(-4)

Comparing both equations, we have

h = -3 and k = -4

hence, the vertex of given equation is (-3,-4).

Answer 2

Vertex = (-3, -4)

Explanation:

The given quadratic equation y = (x + 3)^2 -4

The vertex form of a quadratic equation y = a(x - h)^2 + k

Now let's rewrite the given equation as

y = (x - (-3))^2 - 4

Now let's compare the vertex form with the given equation and find the vertex = (h, k)

Vertex = (-3, -4)

Hope this will helpful.

Thank you.