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How many moles of sodium hydroxide are required to react completely with 23.1 moles of sulfuric acid?

H2SO4(aq) + 2NaOH(aq) = 2H2O(l) + Na2SO4(aq)
Select one:
a) 46.2 moles NaOH
b) 11.6 moles NaOH
c)5.78 moles NaOH
d)23.1 moles NaOH

1 Answer

5 votes

Step-by-step explanation:

Mole ratio of H2SO4 to NaOH = 1 : 2.

Moles of NaOH

= Moles of H2SO4 * (2/1)

= 23.1mol * (2/1)

= 46.2mol. (A)

User Roddy R
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