Answer:
1.274.
Step-by-step explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
∨ ∝ 1/√M.
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
∨₁/∨₂ = √(M₂/M₁)
∨₁ is the rate of effusion of the methane.
∨₂ is the rate of effusion of acetylene gas.
M₁ is the molar mass of methane (M₁ = 16.0 g/mol).
M₂ is the molar mass of acetylene (M₂ = 26.0 g/mol).
∴ The rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂ = ∨₁/∨₂ = √(M₂/M₁) = √(26.0 g/mol)/(16.0 g/mol) = 1.274.