Question

Need help please...answer correctly ​

Answer 1

Answer with step-by-step explanation:

a) Assuming x to be the speed of the boat and y to be the speed of the water, we can write an expression for:

- the distance traveled downstream: 3(x+y)

- the distance traveled upstream: 3.6(x-y)

b) setting expressions in part a equal to each other:

3(x+y) = 3.6(x-y)

3x +3y = 3.6x - 3.6y

3y + 3.6y = 3.6x - 3x

6.6y = 0.6x

y = 0.6/6.6x

y = 1/11x

c) 1/11 * 100 = 9.1%

Answer 2

9.09

Explanation:

x=speed of boat

y=speed of water current

Downstream relative speed = x+y

Upstream relative speed = x-y

Distance remains the same for both upstream and downstream.

a) Distance travelled downstream = speed x time = 3(x+y)

Distance travelled upstream = speed x time = 3.6(x-y)

b) Since both distances are equal, we can write

3(x+y)= 3.6(x-y)

3x+3y = 3.6x-3.6y

6.6y = 0,6x

x=11y: y=x/11

c) Water current has speed as 1/11 times of that of boat

In percent this equals 100/11 = 9.09%