Question

What is the percent composition of Ca(C2H3O2)2?

Select one:
a) 25.3% Ca, 30.4% C, 3.8% H, 40.5% O
b) 40.4% Ca, 24.2% C, 3.1% H, 32.3% O
c) 6.67% Ca, 26.67% C, 40.0% H, 26.67% O
d) 12.5% Ca, 25% C, 37.5% H, 25% O

Answer 1

A

Step-by-step explanation:

RMM of ca(c2h302)2=158

%Ca= 40/158×100=25.3

%C=48/158×100=30.3

%H=6/158×100=3.7

%O=64/158×100=40.5

Answer 2

a) 25.3% Ca, 30.4% C, 3.8% H, 40.5% O

Step-by-step explanation:

Molar mass of Ca(C₂H₃O₂)₂ = 158.160 g/mol

percent composition:

Ca = (40 /158.160 ) × 100

Ca = 25.3%

C = (48 /158.160 ) × 100

C = 30.4%

H = (6 /158.160 ) × 100

H = 3.8%

O = (64 /158.160 ) × 100

O = 40.5%

40.5% + 3.8% + 30.4% + 25.3% = 100%

It means 1st option is correct.