Question

What are the points of discontinuity?

Answer 1

x=−6,x=1

Explanation:

The equation is undefined where the denominator equals 0, the argument of an even indexed radical is less than 0, or the argument of a logarithm is less than or equal to 0

.

Answer 2

The points of discontinuity are x=-6, x=1

Explanation:

The points of discontinuity are the points where the denominator go to zero

We need to factor the denominator

(x-1) (x+3)

y = -----------------------

(x+6) (x-1)

Using the zero product property

x+6 =0 x-1 =0

x=-6 x=1

The points of discontinuity are x=-6, x=1