Question

Hello people ~
help me with the question attached.
Thanks in advance.​

Answer 1

Moles of oxygen

• Given mass/Molar mass
• 64g/32g/mol
• 2mol

Temperature=273+27=300K

Apply ideal gas equation

• PV=nRT
• P=nRT/V
• P=2(0.0831)(300)/10
• P=4.9bar

Answer 2

`\fbox {(2) 4.9}`

Step-by-step explanation:

Applying the Ideal Gas Equation :

`\boxed {PV = nRT}`

Finding n :

• n = 64 g / 32 g/mole (Oxygen is diatomic)
• n = 2 moles

Solving for P :

• P = 2 × 0.0831 × 300 / 10 (Temp. should be converted to K)
• P = 60 × 0.0831
• P = 4.9

∴ The pressure inside the flask in bar is 4.9.