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HELP PLEASE!!! I need help with this question!

HELP PLEASE!!! I need help with this question!-example-1

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Answer:


\large\boxed{PS=10\sqrt5}

Explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:


(QR)/(RP)=(RP)/(RS)

We have:


QR=5,\ RS=20

Substitute:


(5)/(RP)=\dfrc{RP}{20} cross multiply


RP^2=(5)(20)\\\\RP^2=100\to RP=√(100)\\\\RP=10

Use the Pythagorean theorem:


PS^2=PR^2+RS^2

Substitute:


PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=√(500)\\\\PS=√(100\cdot5)\\\\PS=√(100)\cdot\sqrt5\\\\PS=10\sqrt5

HELP PLEASE!!! I need help with this question!-example-1
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