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Find an integer value of b that makes x^2 + bx - 81 factorable.

User Hudon
by
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1 Answer

4 votes

Answer:

b = 80

Explanation:

Given that,

x² + bx - 81

To find,

value of b

What is factorable?

A polynomial equation with highest degree 2 is if factorable when

  1. we can find two terms which when multiples = -81x², ( x² * - 81 = -81x² )
  2. and when add = bx

possible factors:

  1. -1x * 81x = -81x² (Accepted)
  2. 1x * -81x= -81x² (rejected)
  3. 9x * -9x = -81x² (rejected)
  4. -9x * 9x = -81x² (rejected)

Only when -1x , 81x is added -1x + 81x = 80x

so, bx = 80x

b = 80

The equation is x² + 80x - 81

User Hussy
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