Question

Find the perimeter of a regular heptagon with consecutive vertices at A(?1,?2) and B(4, 10)

Answer 1

The perimeter is
`7√(73)` ≈ 59.808 units

Step-by-step explanation:

A regular heptagon is a polygon that has 7 equal sides.

To get its perimeter, we need to get the length of only one side and multiply it by 7

1- getting side length:

We are given that there are two consecutive vertices at (1,2) and (4,10)

The length of the side can be calculated using the distance formula as follows:

Length =
`\sqrt{(x_(2)-x_(1))^2 + (y_(2)-y_(1))^2} = √((4-1)^2+(10-2)^2) = √(73)` units

2- getting the perimeter:

Perimeter = 7 * side length

Perimeter =
`7*√(73)=7√(73)` ≈ 59.808 units

Hope this helps :)