Question

Write the ratios for
sin

X
and
cos

X
.

Answer 1

`sine=(opposite)/(hypotenuse)\\\\\sin X\\\\opposite=√(119)\\hypotenuse=12\\\\\text{substitute:}\\\\\boxed{\sin X=(√(119))/(12)}\\\\cosine=(adjacent)/(hypotenuse)\\\\\cos X\\\\adjacent=5\\hypotenuse=12\\\\\text{substitute:}\\\\\boxed{\cos X=(5)/(12)}`