Question

A satellite moves at a constant speed in a circular orbit about the center of the

Earth at an altitude half the radius of the Earth above its surface. if 'g' is the
gravitational acceleration at the surface of the Earth and Rits radius, then what
will be the speed of the satellite?
O V25R
123R/3
133R/2
VOR

Answer 1

The speed of the satellite is VOR.

Step-by-step explanation:

The speed of the satellite can be calculated using the formula for orbital speed. In a circular orbit, the centripetal force is provided by the gravitational force:

v = sqrt(g * R)

where v is the speed, g is the gravitational acceleration at the surface of the Earth, and R is the radius of the Earth.

Since the satellite is at an altitude half the radius of the Earth above its surface, the radius of its orbit is R/2.

Substituting the values into the formula:

v = sqrt(g * (R/2)) = sqrt(gR/2)

Hence, the speed of the satellite is VOR.