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I need help with the steps on this problem

4 3^squareroot 3 (7+6 3^squareroot 9)

I have the answer but need help with steps

A: 72+28 3^squareroot 3

User MobX
by
6.8k points

1 Answer

5 votes

Answer:


\large\boxed{72+28\sqrt[3]3}

Explanation:


4\sqrt[3]3(7+6\sqrt[3]9)\qquad\text{use distributive property}\ a(b+c)=ab+ac\\\\=(4\sqrt[3]3)(7)+(4\sqrt[3]3)(6\sqrt[3]9)\qquad\text{use}\ \sqrt[3]{a}\cdot\sqrt[3]{b}=\sqrt[3]{ab}\\\\=(4\cdot7)(\sqrt[3]3)+(4\cdot6)(\sqrt[3]{(3)(9)})\\\\=28\sqrt[3]3+24\sqrt[3]{27}\qquad\sqrt[3]{27}=3\ \text{because}\ 3^3=27\\\\=28\sqrt[3]3+24(3)\\\\=28\sqrt[3]3+72

User Ian Fiske
by
6.6k points
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