Question

You get a job delivering water. You calculate how much work is done picking up each 20 L bottle of

water and raising it vertically 1 m. For every 100 bottles you deliver, you will use Select.... (g =
9.8 m/s2)
-196J
-2,000 J
-19,600 J
-196,000J

Answer 1

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.

Step-by-step explanation:

By the Work-Energy Theorem, the work needed to raise vertically 100 bottles of water is equal to the gravitational potential energy, units for work and energy are in joules:

`\Delta W = \Delta U_(g)` (1)

Where:

`\Delta W` - Work.

`\Delta U_(g)` - Gravitational potential energy.

The work is equal to the following formula:

`\Delta W = n\cdot \rho \cdot V \cdot g \cdot \Delta h` (2)

Where:

`n` - Number of bottles, dimensionless.

`\rho` - Density of water, measured in kilograms per cubic meter.

`V` - Volume, measured in cubic meters.

`g` - Gravitational acceleration, measured in meters per square second.

`\Delta h` - Vertical displacement, measured in meters.

If we know that
`n = 100`,
`\rho = 1000\,(kg)/(m^(3))`,
`V = 0.02\,m^(3)`,
`g = 9.807\,(m)/(s^(2))` and
`\Delta h = 1\,m`, then the work done is:

`\Delta W = (100)\cdot \left(1000\,(kg)/(m^(3)) \right)\cdot (0.02\,m^(3))\cdot \left(9.807\,(m)/(s^(2)) \right)\cdot (1\,m)`

`\Delta W = 19614\,J`

The work done by picking up 100 20-L bottles and raising it vertically 1 meter is 19614 joules.