4 out of 16 of the offspring will be both homozygous round and homozygous green.
(below is my work)
S - Round
s - Wrinkled
C - Yellow
c - Green
both parents plants are SsCc
S s
C SC sC x4
c Sc sc
16/4=4
4x1=4
Answer:
Option D. 4
Step-by-step explanation:
Let the alleles be: Round = R
Wrinlkled = r
Yellow = Y
Green = y
The crossing of the plants produces 1 in 4 chance of the orgnism possessing any one of the traits.
Thus, the option is 4
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