Question

How many kilocalories are lost when 874.3 grams of water cools from 84.81 Celsius to 48.20 Celsius?

Answer 1

Answer: 32 kcal

Step-by-step explanation:

`Q= m* c* \Delta T`

Q= heat gained or lost

m= mass of the substance = 874.3 g

c = heat capacity of water = 1 cal/g ° C

`\Delta T={\text{Change in temperature}}=(84.81-48.20)^oC=36.61^0C`

`Q=874.3g* 1cal/g^oC* 36.61^oC`

Q= 32008.1cal=32..0kcal (1kcal=100cal)

Thus heat lost by 874.3 g of iron is = 32 kcal

Heat lost is represented as a negative sign.