Answer:
Choice d is correct.
Explanation:
We have the given function :
![\lim_(x \to \6) x-3/x^(2) -9](https://img.qammunity.org/2020/formulas/mathematics/high-school/43bn8mszgw99j7nebvn5fmt6iwwwu2e4kd.png)
We have to find the limit.
First, simplify the denominator of function.
x²-9 = (x-3)(x+3)
Put this simplification in the function we get,
![\lim_(x \to \6) x-3/(x-3)(x+3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gcqyjig0uqqocsnln09i06ol8jndh0qh37.png)
finally we simplify the function we get,
![\lim_(x \to \6) 1/x+3](https://img.qammunity.org/2020/formulas/mathematics/high-school/5349un08k25c3hjvot7yftbbrr8qotadis.png)
Apply the limit to the function we get,
= 1/9 = 0.1111111
Choice d is correct.