Answer:
Part A)
![p\geq 128\ patties](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yqvrry37u2tc5bjvx852ngob5zjma50qyw.png)
Part B) She will spend more than
![\$142.50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/u6w20aykx07e6hys2bsiv761qwvdx81pot.png)
Explanation:
Let
p-----> the number of hamburger patties
Part A) Luna has to buy at least 16 packages for an upcoming picnic
![p\geq 16*8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qdoexv3z5zaephddfokyx835lmhk3v7l2w.png)
![p\geq 128\ patties](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yqvrry37u2tc5bjvx852ngob5zjma50qyw.png)
Part B) Suppose she actually needs more than 150 hamburgers. How much will she spend?
Let
c---------> the total cost
step 1
Divide 150 hamburgers by 8 (a package of hamburgers)
so
![(150)/(8) =18.75\ package](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s7fxl8u1miu4ramrao0db6ozlp7gjwzz1p.png)
round to the nearest whole number
----> the minimum number of packages
step 2
![c>19*\$7.50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1gtk2xvklvlfhj22r9qeq5hm5ps9qsincm.png)
![c>\$142.50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fkof5jmmrieg0ntquo1ue1ljuvty9h6i16.png)