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Given: 4.5 mL of 0.05 M magnesium sulfate. How many moles of magnesium sulfate do we have?​

User FTWinston
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1 Answer

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Hey there!:

Volume in liters of solution :

4.5 mL / 1000 => 0.0045

Molarity of solution = 0.05 M

Therefore The quantity in moles of magnesium sulfate is :

n = M * V

n = 0.0045 * 0.05

n = 0.000225 moles

Hope that helps!

User ExcellentSP
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