Question

One can safely assume that the 3s- and 3p-orbitals will form molecular orbitals similar to those formed when

H 2s- and 2p-orbitals interact. According to molecular orbital theory, what will be the bond order for the
Cl2+ ion?

a. 0.5
b. 1
c. 1.5
d. 2
e. none of the above

Answer 1

The bond order for the Cl2+ ion will be the same as that of H2, which is 1.

Step-by-step explanation:

According to molecular orbital theory, the bond order for the Cl2+ ion can be determined by comparing it to the bond order of H2. In H2, the 1s orbital of atomic hydrogen interacts with the 1s orbital of another hydrogen atom to form a sigma bonding molecular orbital. The bond order is calculated by taking the difference between the number of bonding electrons and the number of antibonding electrons and dividing it by 2.

In the case of Cl2+, the 3s and 3p orbitals of chlorine interact with each other to form molecular orbitals similar to those formed by H2. Therefore, the bond order of the Cl2+ ion will be the same as that of H2, which is 1.