Question

Need some help asap​

Answer 1

A

Explanation:

Using the trigonometric identity

sin²x + cos²x = 1, hence

cos x =
`√(1-sin^2x)`

cosΘ = √(1 - (
`(√(2) )/(6)`)²

=
`\sqrt{1-(2)/(36) }`

=
`\sqrt{1-(1)/(18) }` =
`\sqrt{(17)/(18) }` and

`\sqrt{(17)/(18) }` =
`(√(17) )/(3√(2) )`

multiply numerator/ denominator by
`√(2)`

=
`(√(34) )/(6)` → A