Question

Find (f + g)(y).
f(y) = 1/y
g(y)= y2+2y-5

Answer 1

For this case we have given two functions f (y) and g (y), then:

`(f + g) (y) = f (y) + g (y)`

We have:

`f (y) = \frac {1} {y}\\g (y) = y ^ 2 + 2y-5`

Adding we have:

`(f + g) (y) = \frac {1} {y} + y ^ 2 + 2y-5`

Finally:

`(f + g) (y) = y ^ 2 + \frac {1} {y} + 2y-5`

Answer:

`(f + g) (y) = y ^ 2 + \frac {1} {y} + 2y-5`

Answer 2

(f+g)(y) = 1/y + y2+2y-5

Explanation:

To find (f+g)(y) we literally add the two expressions together. The expression becomes:

(f+g)(y) = f(y) + g(y)

= 1/y + y2+2y-5