Question

1.) C6H12O6 (aq) is a(an)?

A. Ion in solution
B. Dilute solution
C. Ion in a crystal
D. Dissolved Molecule

2.) 2.60 moles of LiCl is dissolved in 230. mL of water. What is the resulting molarity? ( Hint: Change unit mL to L before you divide.)
A. 2.6 M
B. 11.3 M
C. 2.30 M
D. 11 M

Answer 1

1) D. Dissolved Molecule

2) C. 11.30 M

Step-by-step explanation:

Q1:

• Glucose (C₆H₁₂O₆) is a non-polar molecule.

• When it is dissolved in water, it will be a dissolved molecule.

• It can not be ionized in water.

• So, the right choice is: D. Dissolved molecule.

Q2:

• The molarity is the no. of moles of dissolved solute in a 1.0 L of the solution.

M = (n)solute (1000/V (mL) of the solution)

n of LiCl = 2.60 mol, V = 230.0 mL.

∴ M = (n)solute (1000/V (mL) of the solution) = (2.60 mol)(1000)/(230.0 mL) = 11.30 M.