Question

What is the equation of the line that passes through the points (-3, -2) and (1, 6)?

Answer 1

y = 2x +4

Explanation:

m =
`(y_(2) -y_(1) )/(x_(2) - x_(1) )`

y -
`y_(1)` = m ( x -
`x_(1)` )

~~~~~~~

(1, 6)

(- 3, - 2)

m = 2

y - 6 = 2 ( x - 1 ) <------ ( point-slope form )

y = 2x + 4 <------- ( slope-intercept form )

2x - y = - 4 <------ ( standard form )