Question

Let a= x2 +4 rewrite the following equation in terms of a and set it equal to zero. (X2 + 4)2 + 32 = 12x2 + 48 in the resulting equation what is the coefficient of the a term and what is the constant

Answer 1

`Answer: \\ {( {x}^(2) + 4) }^(2) + 32 = 12 {x}^(2) + 48 \\ \Leftrightarrow {a}^(2) + 32 = 12( {x}^(2) + 4) \\ \Leftrightarrow {a}^(2) + 32 = 12a \\ \Leftrightarrow {a}^(2) - 12a + 32 = 0 \\ \Rightarrow Coefficients:1, \: -12. \: Constant:a`