Question

Foil: (x+9)(3x-4)

Answer:


Factor: 6r5s + 4r4s2- 8r2s
Answer:



1. Write an equation in which the quadratic expression equals 0. Show the expression in factored form and explain what your solutions mean for the equation. Show your work. Answer:

Answer 1

QUESTION 1

The given binomial is;

`(x+9)(3x-4)`

First terms are multiplied:
`x* 3x=3x^2`

Outside terms are multiplied:
`x* -4=-4x`

Inside terms are multiplied:
`9* 3x=27x`

Last terms are Multiplied:
`9* -4=-36`

This gives us;

`=3x^2-4x+27x-36`

`=3x^2+23x-36`

QUESTION 2

We want to factor

`6r^5s+4r^4s^2-8r^2s`

The HCF is
`2r^2s`

We factor to get;

`2r^2s(3r^3+2r^2s-4)`

QUESTION 3;

`x^2+x-2=0`

Split the middle term;

`x^2+2x-x-2=0`

Factor

`x(x+2)-1(x+2)=0`

`(x+2)(x-1)=0`

`(x+2)=0,(x-1)=0`

`x=-2,x=1`

The solutions are;

`x=-2` and
`x=1`

These are the x-intercepts of the graph of the function

`f(x)=x^2+x-2`