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Cual es la ecuación de la recta que pasa por el punto (2;-1/2) y tiene de pendiente m=-2/3

User Roman Mindlin
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1 Answer

23 votes
23 votes

Answer:

y = (-2/3)x + 5/6

Explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m". To find the value of "b", you can plug the slope and the values from the point (2, -1/2) into the general equation.

m = -2/3

Point (2, -1/2):

x = 2 and y = -1/2

y = mx + b <----- Slope-intercept form

y = (-2/3)x + b <----- Insert -2/3 in "m"

-1/2 = (-2/3)(2) + b <----- Insert "x" and "y" values from point

-1/2 = -4/3 + b <----- Multiply -2/3 and 2

-3/6 = -8/6 + b <----- Give the fractions common denominators

5/6 = b <----- Add 8/6 to both sides

Thus, the equation of the line is:

y = (-2/3)x + 5/6

User Ayush Surana
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