Question

HELP

What is the spring constant of a spring that is compressed by 0.250 cm when a force of 35 N is applied?


a. 140N/cm

b.100N/cm

c.200N/cm

d.150N/cm

Answer 1

a. 140 N/cm

Step-by-step explanation:

The relationship between force applied, spring constant and compression/stretching of a spring is

`F=kx`

where

F is the force applied

k is the spring constant

x is the compression/stretching

In this problem, we have:

x = 0.250 m is the compression

F = 35 N is the force applied

Substituting and re-arranging the equation, we find the spring constant:

`k=(F)/(x)=(35 N)/(0.250 cm)=140 N/cm`