Question

A certain quantity of a gas occupies 61.3 mL at 68◦C. If the pressure remains constant what would be the volume of the gas at 128◦C?

Answer 1

72.1 mL

Step-by-step explanation:

Since the pressure of the gas remains constant, we can use the following gas law:

`(V_1)/(T_1)=(V_2)/(T_2)`

where:

`V_1 = 61.3 mL` is the initial volume of the gas

`T_1 = 68^(\circ)=341.15 K` is the initial temperature

`V_2 = ?` is the final volume of the gas

`T_2 = 128^(\circ)=401.15 K` is the final temperature of the gas

Re-arranging the equation and solving for V2, we find:

`V_2 = V_1 (T_2)/(T_1)=(61.3 mL)(401.15 K)/(341.15 K)=72.1 mL`