Question

In a test of Charles' law, a gas inside a cylinder with a movable piston is heated to

315°C. The initial volume of gas in the cylinder is 0.30 L at 25°C. What will be the final
volume when the ttemperature is 315°C?

Answer 1

3.78 L

Step-by-step explanation:

The Charles' Law equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the final volume by plugging the give values into the equation and simplifying.

V₁ = 0.30 L V₂ = ? L

T₁ = 25 °C T₂ = 315 °C

V₁ / T₁ = V₂ / T₂ <----- Charles' Law equation

(0.30 L) / (25 °C) = V₂ / (315 °C) <------ Insert values

0.012 = V₂ / (315 °C) <----- Divide 25 from 0.30

3.78 = V₂ <----- Multiply both sides by 315