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Which is the completely factored form of f(x) = x^3 - 2x^2 - 5x + 6?

User Psy
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1 Answer

2 votes

Answer:

(x - 1)(x - 3)(x + 2).

Explanation:

f(1) = 1^3 - 2(1)^2 - 5(1) + 6

= 1 - 2 - 5 + 6

= 0

so one factor is (x - 1) (by the Factor Theorem).

Divide f(x) by x - 1 we get:

x- 1) x^3 - 2x^2 - 5x + 6 ( x^2 - x - 6 <------ answer

x^3 - x^2

-x^2 - 5x

-x^2 + x

-6x + 6

-6x + 6

= x^2 - x - 6

= (x - 3)(x + 2).

User GKV
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4.8k points