Question

State the amplitude, period, and phase shift for y=2sin3(x-π/4)

Answer 1

Amplitude 2

Period:
`(2\pi)/(3)`

Phase shift:
`(\pi)/(4)` units to the right

Explanation:

The given function is
`y=2\sin(3(x-(\pi)/(4)))`

This function is of the form
`y=A\sin(Bx+C)`

where
`A=|2|=2` is the amplitude.

The period is
`(2\pi)/(B)= (2\pi)/(3)`

This function is shifted
`(\pi)/(4)` units to the right